Are you about to give IBPS or SBI PO/Clerk, LIC, NICL, OICL, AAO, SSC, Railway exam?

Quantitative Analysis or maths in these exams is easy for students having mathematics as major in their 10+2.

But it may sound difficult to those who had rarely solved maths questions. But wait, who hadn’t solved a single maths question in their entire life?

Do you borrow things in shops or do you bargain with your vegetable seller?

If yes, then how do you count the rate in grams when the seller tells you in Kg? This is also maths. Mind it! Questions asked in the real exams are slightly tough than those you solve while standing in the shop.

This toughness can be overcome by practice.

**How to practice the Quant Section?**

Simple. First learn all the formulas, but do not learn them at once.

In maths, some formula you learn by continuous practice. But some you learn by continuous revision.

**Formula learned by Practice.**

All the basic formula like S.I. = PxRxT/100 are learned by practice.

These formulas are the basis of formation of millions of new formulas. But they themselves are invented by thousand trial and error and then are accepted worldwide.

These formulas can be learned by solving 10 or 20 questions based on them every week.

If you will do more practice with them, they will become more easy. But they are not much scoring because questions based on them are mostly direct.

And direct questions are easy to solve, hence they are less asked in the IBPS exams.

**The formulas which are learned by Revision.**

Those formulas which are derived from the basic formulas with the situation of the question are learned by continuous practice. For example R = S.I.x100/PxT

This formula is derived from the famous Simple interest formula when the situation in question was to know the rate of interest.

Questions based on these formulas are favorite for IBPS paper makers. So if you practice all the famous formulas continuously, your chances of selection increases by three times.

**Topicwise discussion**

**Time and Work**

Simply taken, this section can be easily solved when you brought up all the data into one day (or hour) work by single person.

This can be done by the following method.

- If X can do a piece of work in n days, then his one day work is 1/n.

For example, if Amrita can do a piece of work in 6 days then her one day work will be ⅙.

- If X can do a piece of work in n hour and Y can do the same work in m hours then their combined one hour work will be, 1/n + 1/m.

Note: your calculation speed must be good to reach the result quickly with accuracy. Sometimes you can guess the answers depending on the options given if you have a good practice.

**Time and Distance**.

This section has only one basic formula,

Speed = Distance/Time.

Rest are discovered based on situations according to the question.

**Simplification**

Simplification is one of the most important part of Quantitative Aptitude section of any competitive exam. And is totally dependent of the simple concept of V-BODMAS

Rules of Simplification

**V** → Vinculum

**B** → Remove Brackets – in the order ( ) , { }, [ ]

**O** → Of

**D** → Division

**M** → Multiplication

**A** → Addition

**S** → Subtraction

And it contains all the following sections which are responsible for 5-10 marks in exam.

**Number System**

**HCF & LCM**

**Square & Cube**

**Fractions & Decimals**

**Surds & Indices**

**Boats and Stream**

In this section questions are asked based on realtime assumption of a boat flowing into a running stream.

The basic concept involved are,

**Downstream/Upstream:**

- In water, the direction along the stream is called
**downstream**. - The direction against the stream is called
**upstream**. - If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then:

Speed downstream = (u + v) km/hr.

Speed upstream = (u – v) km/hr.

- If the speed downstream is a km/hr and the speed upstream is b km/hr, then:

Speed in still water = | 1 | (a + b) km/hr. |

2 |

Rate of stream = | 1 | (a – b) km/hr. |

2 |

**Problems based on Trains**

Here the question asked is to calculate the length of train or platform or some bridge etc. The basic concept employed in this section is completely related with the question asked in Speed and Time but are slightly tricky.

The tricks are,

**km/hr to m/s conversion**

a km/hr = | a x | 5 | m/s. | ||

18 |

**m/s to km/hr conversion**

a m/s = | a x | 18 | km/hr. | ||

5 |

- Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres.
- Time taken by a train of length l metres to pass a stationary object of length b metres is the time taken by the train to cover (l + b) metres.
- Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u – v) m/s.
- Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
- If two trains of length a metres and b metres are moving in opposite directions at um/s and v m/s, then:

**Simple Interest and Compound Interest**

There are only two basic formulas for this section.

Simple Interest,

SI = PxR%xT

A=P+SI

And, for Compound Interest,

A= P (1+r/100)

**Profit and Loss**

You must be familiar with the concept involved in Profit and Loss. This is the section I have taken example from, in the starting of this page. You often do this calculation in the shops where you go to buy household items.

The questions asked are also of the same type. A shopkeeper or retailer of someone who buys something are the starting points of this section.

The basic concepts involved are,

- Cost Price (CP) – The price at which the good bought.
- Selling Price (SP) – The price at which it is sold to someone else.
- Profit – The surplus amount the seller gets on the good he buys = SP – CP.
- Loss – The negative amount seller has to pay from his pocket when he sells something,
- Percentage (Profit or Loss) = Percent he loses or gains on CP.

% = P (or L)x100/CP

**Ratio and Proportions**

Ratio and Proportions is an important topic from exams. It can come as an individual question or a part of data interpretation (DI).

**Ratio**

When two numbers are represented in the form of another; this is done by expressing one number as a fraction of another.

Thus, we have a:b; where a is the **antecedent**, and b is the **consequent** (Sometimes these terms are also used in questions).

Example, 2:5 or simple 2/5.

**Proportion**

Proportions is where two ratios are compared and/or equated.

When a:b is a ratio and c:d is another ratio, and if they are equated, then they can be re-written as a:b :: c:d. ( the :: sign means ‘equal to’ and is read as ‘is to’)

Therefore, a:b = c:d or, a/b=c/d

Example,

1:2 = 2:4 can be written as,

1:2::2:4 or, 1/2 =2/4.

**Percentage**

You have always got your marks in percentage. GDP of country is also calculated in percentage. Performance of any individual or industry is always calculated in percentage.

The questions asked in the exams are all dependent on these types. So you must understand the base of percentage. This is very simple and comprises of only one line,

Anything which is compared to 100 is known as percentage.

Means, 10% = 10 of the 100 things.

50% = 50 of the 100 things = half of the given things.

75% = 75 of the 100 things = 3/4th of the given things.

100% = Everything of the given items.

200% = Double of the given items.

1000% = 10 times.

**Problems on Ages**

Very simple calculations like, if your present age is 21 years, what will be your age after 5 years or before 2 years. that’s it.

But problem becomes complex when ratio proportion or percentage are involved.

So you have to be conscious about the language involved in the question. Keep your presence of mind with you because simple questions are sometime more hurting when your answer becomes wrong just by a simple mistake.

**Data Interpretation (DI)**

Data interpretation is the most scoring and time consuming section in IBPS and other competitive examinations. In quantitative aptitude section you can see at least 2 data interpretation sets each having 5 questions. So if you solve all the question correct you can score 10 marks with complete accuracy. rest sections are much easier than this.

Some good practices for solving Data interpretation are

- Be clear to what is given and what is asked.
- Write the given data and the data asked to increase your accuracy. Practice this at home.
- If a question too much lengthy, leave it!.
- Focus only on useful data because sometimes there are many scrap to confuse you.
- Never lose your heart if you see lot of data. Try to accumulate the necessary one out.
- Do only what is asked. Don’t try to keep data ready before solving. Solve simultaneously with the question because examiners know the student’s mindset and they love tricking you.
- Take approximate value wherever possible.
- If only relative values are asked, don’t calculate the actual values.

Quantitative Aptitude is the section which is most time consuming while in preparation and in exams. Your approach should be different for this section.

Don’t think to solve all the questions. Try to get sectional cut-off first and then to score good. Manage your time so that you should not give more than the allotted time for each section.

I will be discussing each section in detail and with tricks and shortcuts. Tell me if you have any confusion. Share your love!!

Sumit says

Hello Sir,

Thank you for giving this advice. But I have a problem.

Earlier I was not knowing about the difference between these two types of formulas. But now it is more clear to me.

Sir please provide us the important formulas which we can practice to get good marks. Please help sir, Please.

Avi says

Hi Sumit,

Sure, will work on the formulas and will provide you before your exam.